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Challenge 291 : A Choice Challenge

Two problems this week! Try (b) if you are up for a challenge with lots of careful logical thinking.

(a) If you select any five positive integers it will always be possible to find at least one group of three of them that sum to a multiple of three. For example, if I selected 3, 6, 8, 11, 16 then I could choose 3, 8 and 16 – with a sum of 27 – or I could choose 6, 11 and 16 – with a sum of 33.

There are other possible groups of three I could use in this example but they will all contain 16.

Why must this be?

(b) For a further (quite extreme) challenge, if I wanted to be able always to select four numbers from any group of n positive integers so that the sum of the four numbers would be a multiple of four, what is the smallest possible value of n?