a You are faced with 12 identical pairs of Wellington boots that have been lined up in a row of 24 boots, but with left and right boots jumbled up. Show that it is possible that the boots are arranged in such a way that no set of 10 consecutive boots contains 5 pairs of boots.

b Now you are faced with 15 identical pairs of Wellington boots that have been lined up in a row of 30 boots, but with left and right jumbled up. Is it possible that the boots are arranged in such a way that no set of 10 consecutive boots contains 5 pairs of boots?

c Finally, and most challengingly, you are faced with n identical pairs of Wellington boots that have been lined up in a row of 2n boots, but with left and right jumbled up. For which values of n (greater than or equal to 5) is it is possible that the boots are arranged in such a way that no set of 10 consecutive boots contains 5 pairs of boots?

Note: in all parts of this challenge any right boot may be put with any left boot to make a pair.